What is the equation, in slope-intercept form, of the line that is perpendicular to the line y – 4 = –Two-thirds(x – 6) and passes through the point (−2, −2)? y = –Two-thirdsx – Ten-thirds y = –Two-thirdsx + Ten-thirds y = Three-halvesx – 1 y = Three-halvesx + 1

The equation is y = Three-halvesx + 1Step-by-step explanation:That line should be perpendicular to the given line : y-4 = -2/3 (x-6) andIt passes through (-2,-2)Write the equation in slope-intercept form as;y-4= -2/3 (x-6)y-4=-2/3x + 4y= -2/3x + 8The slope m₁, of the equation is -2/3For perpendicular lines, m₁*m₂= -1So,finding m₂ where m₁ = -2/3-2/3 * m₂ = -1m₂ = -1 * - 3/2 = 3/2The equation of the line passing through point (-2,-2) with m₂=3/2 will be;y--2/x--2 = 3/2y+2/x+2=3/22(y+2)=3(x+2)2y+4=3x+62y=3x+6-42y=3x+2y=3/2x +1  ⇒⇒Three-halves *x+1Learn MoreEquation of perpendicular lines : : equation, slope-intercept form, perpendicular #LearnwithBrainly